Given Ilm and mz1 = 60°, select all angles that are also equal to 60°.

Step-by-step explanation:

Ok, so the given is actually l║m, meaning l and m are parallel. This means that certain angles will be the exact same value.

I haven't studied geometry for 4 years, so forgive me, I don't remember he exact terminology nor the postulates/theorems that state this, but take my word for it.

∠1=∠2=∠3=∠4

Therefore, since∠1=60°, that means that ∠2, ∠3, and ∠4 also equal 60°.

∠2, ∠3, ∠4

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: