What are the x-intercepts of y=4x^2-16

(-2,0) and (2,0)

Step-by-step explanation:

To find the x intercepts of a graph, you need to set the y to 0. This is because a graph only intersects the x axis at the line y=0. Hence:

Factor:

The x intercepts are at (-2,0) and (2,0). Hope this helps!

The x intercepts are -2 and 2

Step-by-step explanation:

y=4x^2-16

Set equal to zero to find the x intercepts

0 =4x^2-16

Factor

0 = 4(x^2 -4)

Factor again, noticing the difference of squares ( a^2 - b^2) = (a-b)(a+b)

0 = 4(x-2) (x+2)

Using the zero product property

0 = x-2   0 = x+2

x =2          x = -2

The x intercepts are -2 and 2

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )

step-by-step explanation:

goog be able to you with that maybe