Multiple chickens and rabbits are in a cage. There are 20 more chickens than rabbits and together, there are 256 legs in all. How many rabbits are there? Please explain

c = −108 and r = 118

Step-by-step explanation:

Since we know that chickens have  2  legs and rabbits have  4  legs, we can set up a system of equations to solve the problem.

Let  c  be the number of chickens and  r  be the number of rabbits.

for legs, we can write the equation out in word form as:

(number of legs per chicken)(number of chickens) + (number of legs per rabbit)(number of rabbits) = (total number of rabbits)

In algebraic form, this equation would look like this:

2 c  +  4 r  =  256

20+r +r = 256

Now we can use elimination (or substitution) to solve for c and r:

The equation can be reduced by dividing both sides by 2:

c  +  2 r  =  128

Solve for r.

20+r +r = 256

2r = 236

2r/2 = 236/2

r = 118

Substitute and solve for c.

c + 2(118) = 128

c + 236 = 128

c = -108

v = 1/3 a^2h

step-by-step explanation:

the volume is 1/3 a^2h.

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph