Mathematics, 07.06.2020 07:58 shalcarter2001

The point-slope form of the equation of the line that passes through (44, -3) and (12, 1) is y - 1 = 4(x – 12). What is the standard form of the equation for this line?
x - 4y = 8
x - 4y = 2
4x - y = 8
4x-y=2

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The point-slope form of the equation of the line that passes through (44, -3) and (12, 1) is y - 1 = 4(x – 12). What is the standard form of the equation for this line?x - 4y = 8x - 4y = 24x - y = 84x-y=2

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Another question on Mathematics

The point-slope form of the equation of the line that passes through (44, -3) and (12, 1) is y - 1 = 4(x – 12). What is the standard form of the equation for this line?
x - 4y = 8
x - 4y = 2
4x - y = 8
4x-y=2