I WILL MARK BRAINLIEST
look at attachment

see below

Step-by-step explanation:

h(t) = –gt^2 + v0t + h

where g is 1/2 the gravity constant and v0 is the initial velocity and h is the initial height

h(t) = –16t^2 +49t + 0

h(t) = –16t^2 +49t

Factor out t

0 = t(-16t+49)

The zeros are at

t= 0 and   -16t = -49

                      t = 49/16

The vertex  (or max) is 1/2 way between the zeros

(0+ 49/16)  /2 = 49/32  =1.53125

Round to the nearest hundredth

x = 1.53

The height is

h(1.53) = 1.53(-16 * 1.53 +49)

          37.5156

To the nearest hundredth

           37.52

The range is the values that height can take

0 ≤h≤37.52

There is a maximum height because eventually the effects of gravity going down outweigh the effects of the initial velocity going up

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

i hope this you, and have a wonderful day!