Use Gauss–Jordan reduction to solve each of the following systems. (a) x1 + x2 =−1 4x1 −3x2 = 3 (b) x1 +3x2 + x3 + x4 = 3 2x1 −2x2 + x3 +2x4 = 8 3x1 + x2 +2x3 − x4 =−1 (c) x1 +x2 +x3 =0 x1 −x2 −x3 =0 (d) x1 + x2 +x3 + x4 =0 2x1 + x2 −x3 +3x4 =0 x1 −2x2 +x3 + x4 =0

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation:

any of them that add up to 180 degrees.