The set of points P(0, 3), Q(2, 0), R(4, -3) are collinear and the line has a slope of . -3/2
3/2
- 1/2
1/2

-3/2,collinear.

Step-by-step explanation:

slope of PQ=(0-3)/(2-0)=-3/2

eq. of line PQ is

y-3=-3/2(x-0)

y-3=-3/2 x

or2y-6=-3x

or 3x+2y=6

if R(4,-3) lies on it,then

3(4)+2(-3)=6

12-6=6

or 6=6

which is true.

Hence points P,Q,R are collinear.

and line has aslope=-3/2

c

-by-step explanation:

it would be c