Convert the following complex number into its polar representation: -40
O A. 4(6052isang
37
B. 2(cos(+ isin)
C. 16(COST* isin x)
O D. -4(cose i sin

The correct option is B. 3√2(cos(135°) + i·sin(135°))

Step-by-step explanation:

The complex number is given as : 3 - 3i

Now, comparing this with the standard for : a + bi

⇒ a = 3 and b = -3

Now, r = √a² + b²

⇒ r = √18

⇒ r = 3√2

Now, The polar form is represented by :

z = r(cosθ + i·sinθ)

⇒ z = 3√2(cos 135° + i·sin 135°)

Therefore, the correct option is B. 3√2(cos(135°) + i·sin(135°))

Step-by-step explanation:

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

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26

step-by-step explanation: