A fair coin is tossed, and a marble is chosen from the bag whose contents are shown below. 3 red marbles, 3 blue marbles, and 4 green marbles. What is the probability of the coin landing heads up and a blue (B) marble being randomly selected?

3/20

Step-by-step explanation:

Red = 3

Blue = 3

Green = 4

Total = 3+3+4 = 10

Pr (red) = 3/10

Pr blue) = 3/10

Pr (green) = 4/10

Where Pr = probability

You either have a head or a tail when tossing a coin

Probability of having head = 1/2

Probability of having tail = 1/2

The probability of the coin landing heads up and blue marble = Probability of head ×Pr (blue)

= 1/2 × 3/10

the probability of the coin landing heads up and blue marble = 3/20

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step-by-step explanation:

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.