A four-person committee is chosen from a group of eight boys and six girls. If students are chosen at random, what is the probability that the committee consists of all boys? StartFraction 4 Over 1001 EndFraction StartFraction 15 Over 1001 EndFraction

0.07

Step-by-step explanation:

in the group, we can have only 4 persons.

we have 8 boys, and 6 girls.

We want to find the probability that in the comite we have only boys.

Ok, for the first selection, the probability of selecting a boy is equal to the number of boys divided the total number of the group ( 8 + 6 = 14) this is

p1 = 8/14.

For the second selection we do the same, but we already slected a boy, so now the number of boys is 7, and the total number of posibilities is 13.

p2 = 7/13.

for the third selection we do the same, in this case the probability is

p3 = 6/12

for the fourth selection the probability will be:

p4 = 5/11

The joint probability, of all the events happening at the same time, is equal to the product of the singular probabilities:

P = p1*p2*p3*p4 = (8/14)*(7/13)*(6/12)*(5/11) = 0.07

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)

step-by-step explanation: