~Help me with this please! I will mark as BRANLIEST and if you answer correctly there would be a 55 point question for you!!!

Simply here we use system of 2 equations.

Step-by-step explanation:

Let x be the cost of one small shirt and let y be that of one large shirt.

(4x +14y =210) (-3)

12x +11y =110

-12x - 42y= -630 note:cross 12x and - 12x

12x +11y =110

-42y +11y = - 630 +110

-31y = -520

Y=520/31

Replace y in second equation:

12x +11y =110

12x +11(520/31) =110

12x +5720 =110

12x =110 - 5720/31

X= - 385/62

So one small shirt costs - 385/62 $

And a large one costs 520/31 $

Though I think there's something wrong in this problem since i verified my answer using calculator the same prices are obtained and as u see the cost of a small shirt is negative which is unbelievable.. So plz make sure from anyone else. I tried my best to help.

sorry, can't i suggest going to algebra.com

step-by-step explanation:

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1