An air traffic controller at an airport sights a plane at an angle of elevation of 28º. The pilot reports that the plane's altitude is 4500 feet.

To the nearest foot, what is the distance from the control tower to the plane?

3190 ft

8463 ft

2113 ft

9585 ft

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

answer: a.

step-by-step explanation: the answer is a. because, you need to converge the fractions to find a solution.

practice. practice. practice.