Professor Melendez has 10 students in her college algebra class. Their ages are shown below. 19, 27, 19, 18, 18, 18, 47, 19, 20, 18

The mean age of the students in the class is 22.3. The median age of the students is 19.

There are two outliers in the data from Professor Melendez’s class: 27 and 47.

When the outliers are removed, what is the mean age of the remaining students? Round your answer to the nearest tenth
What is the median age of the remaining students?

Mean: 18.6 years old

Median: 18.5 years old

Step-by-step explanation:

Mean = average (add all numbers then divide by the number of numbers in the data set)

To find the mean, start by adding all of the numbers except for the outliers.

19 + 19 + 19 + 18 + 18 + 18 + 18 + 20 = 149

We added 8 numbers, so divide the sum by 8.

149/8 = 18.6

Therefore, the mean without outliers is 18.6 years old.

Median = middle (order numbers from least to greatest, then find the middle)

To find the median, order the numbers from least to greatest.

18, 18, 18, 18, 19, 19, 19, 20

Now, find the middle.

(Since there are an even number of numbers, select the two numbers in the middle.)

18, 18, 18, 18, 19, 19, 19, 20

Now, add these numbers and divide by 2.

18 + 19 = 37

37/2 = 18.5

Therefore, the median without outliers is 18.5 years old.

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

⭐⭐

i think is 3 and 6. this took me 10 min to think.hope to and hope that my answer is brainliest.(follow me )