Find the measure of arc EB. Circle A is intersected by line CD at points D and E and line CB at point B, forming angle ECB outside of the circle, the measure of angle ECB is 25 degrees, arc EB is 4x plus 16 degrees, and arc DB 7x plus 6 degrees.

= 96°

Step-by-step explanation:

From the figure attached,

m∠ECB = 25°

degrees

degrees

From the theorem of secants intersecting outside the circle,

m∠ECB =

25° =

25° =

50 = 3x - 10

3x = 60

x =

x = 20

= (4 × 20 + 16)°

        = (80 + 16)°

        = 96°

Therefore, measure of arc EB is 96°.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

a

step-by-step explanation: