Perpendicular help i need help

m₁×m₂ = -1

m₁ = 3 and m₂ = -1/3

3×-1/3 = -1

-1 = -1

Hence proved, the given two lines are perpendicular.

Step-by-step explanation:

You can prove that the two lines are perpendicular if the following condition holds true.

m₁×m₂ = -1

Where m₁ is the slope of line 1 and m₂ is slope of line 2

So first you have to find out the slope of each line.

You are given 2 equations

y = 3x + 5         eq. 1

6y + 2x = 1       eq. 2

You have to write these equations in slope-intercept form to find out their slopes.

The slope-intercept form is given by

y = mx + b

Comparing the general form with eq. 1

y = 3x + 5

We notice that the slope is m₁ = 3

Now convert the eq. 2 into slope-intercept form

6y + 2x = 1       eq. 2

6y = -2x + 1

y = (-2x + 1)/6

y = -1/3x + 1/6     eq. 2

Comparing the general form with eq. 2

y = -1/3x + 1/6

We notice that the slope is m₂ = -1/3

Now we have slopes of both lines so let us test whether they are perpendicular or not

m₁×m₂ = -1

m₁ = 3 and m₂ = -1/3

3×-1/3 = -1

-1 = -1

Hence proved, the given two lines are perpendicular.

answer: 1) twenty-seven times y

              2) twenty-seven multiplied by y

the answer is thin because within context, the stanza concludes the and frail tone the people have toward each other, and the fact that it would be thin, makes the most sense compared to "pliable" or "not hard or firm to the touch". hope this , good luck.

step-by-step explanation:

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