A triangle has vertices (-1,2), (-2,3) and (-3,1). Find the lengths of all three sides of the triangle. Is it isosceles? Is it a right triangle? 1 point No, not an isosceles or a right triangle It is an isosceles but not a right triangle. It is a right triangle but not an isosceles triangle. It is both an isosceles and a right triangle

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Step-by-step explanation:

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step-by-step explanation:

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option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.