Given the table of values below, which of the following ordered pairs are found on the graph of the inverse function?
x. -2,-2,0,1,2 f(x) 2,7,12,17,22

A. (-2,-2),(-1,-7), (0, -12), (1,-17), (2, -22)
B. (-2, 2), (-7,1),(-12, 0). (-17, -1),(-22, - 2)
O C. (2,-2), (7.-1), (12, 0), (17. 1). (22, 2)
D. (2,-2), (1, -7), (0, -12), (1, -17), (2, -22)

56

step-by-step explanation:

a 270° rotation about point p says on e d g e n u it y (had to space it out because it says it's a misspelling so i couldn't submit it

my guess is

step-by-step explanation:

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.