WHAT IS THE PYTHOGERON TRIPLETS IF ONE NUMBER IS 36

Step-by-step

Let the given number be n>2.

For n even, n2+((n/2)2–1)2=((n/2)2+1)2.

For n odd,  n2+((n2–1)/2)2=((n2+1)/2)2

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standard form of a pythagorean triplet is 2m, m²+1, m²-1

let us take 2m as 36. so

2m=36, m=36/2

therefore m=18

m²+1  =18²+1   = 324+1   =325

m²-1   =18²-1    = 324-1    =323

therefore  36,325,323 form a pythagorean triplet.

For checking, 36²+323² should be equal to 325²

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