N 2) A sample of size n= 49 is obtained. The population mean

is m= 80 and the population standard deviation is s = 14.

Find the probability that the sample has a sample average

between 78.3 and 85.1, (5 points)

-

0.7969

Step-by-step explanation:

Given that: A sample of size n= 49 is obtained. The population mean  is m= 80 and the population standard deviation is s = 14.

The z score measures the number of standard deviation by which the raw sore is above or below the mean. It is given by the equation:

For x = 78.3, the z score is:

For x = 85.1, the z score is:

P(78.3<x<85.1) = P(-0.85<z<2.55) = P(z<2.55) - P(z<-0.85) = 0.9946 - 0.1977 = 0.7969