On a coordinate plane, triangle L M N has points (2, 1), (1, 1), (1, 3). Triangle L prime M prime N prime has points (negative 4, negative 4), (negative 3, negative 4), (negative 3, negative 2). Which sequence of transformations produces TriangleL'M'N' from TriangleLMN? a translation 5 units down and 2 units to the right followed by a reflection across the y-axis a reflection across the y-axis followed by a translation 5 units down and 2 units right a translation 5 units down and 2 units to the left followed by a reflection across the y-axis no sequence of transformations

(A)a translation 5 units down and 2 units to the right followed by a reflection across the y-axis

Step-by-step explanation:

If a point is reflected across the y-axis, the y-coordinate remains the same, but the x-coordinate is transformed into its opposite.

Triangle LMN has points (2, 1), (1, 1), (1, 3).

Triangle L'M'N' has points (-4,-4), (-3,-4), (-3,-2).

From the given options:

Option A: A translation 5 units down and 2 units to the right followed by a reflection across the y-axis

Given the points: (2, 1), (1, 1), (1, 3) of Triangle LMN

Therefore, the sequence of transformation in Option A produces Triangle L'M'N'.

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

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step-by-step explanation: