A chemical company makes two brands of antifreeze. The first brand is 40%pure antifreeze, and the second brand is 90%pure antifreeze. In order to obtain 160

Complete question:

A chemical company makes two brands of antifreeze. The first brand is 40% pure antifreeze, and the second brand is 90% pure antifreeze. In order to obtain 160 gallons of a mixture that contains 60% pure antifreeze, how many gallons of each brand of antifreeze must be used?

Amount of 40% pure antifreeze = y = 96gallons

Amount of 90% pure antifreeze = ((160-y) = (160 - 96) = 64gallons

Step-by-step explanation:

Brand A = 40% pure

Brand B = 90% pure

Therefore to obtain 160 gallons that contains 60% pure antibfreeze:

Let y = Amount of 40% pure antifreeze required

Therefore (160 - y) = Amount of 90% pure antifreeze required.

Expressing mathematically,

0.4y + (160 - y) (0.9) = 160×0.6

0.4y + 144 - 0.9y = 96

-0.5y = 96 - 144

-0.5y = - 48

y = 48 / 0.5

y = 96

Amount of 40% pure antifreeze = y = 96gallons

Amount of 90% pure antifreeze = ((160-y) = (160 - 96) = 64gallons

i think it would be 43 movies that would have to be watched.

step-by-step explanation:

think about it. for the second plan, every month is 8 dollars. 8 x 12= 96. so thats the number for the second plan. now for the first plan, its annual meaning you have to pay 10 dollars every year. so now you have to get an equivalent amount of 86 since 96-10=86. 86 divided by 2 since every movie costs 2$ then you would have to watch 43 movies a year to get the same as the second plan. i really hoped this . have a wonderful day as well!

2

step-by-step explanation: