A parabola in the coordinate plane passes through the points (-4,7) (3,0) (8,10). When the quadratic function associated with this parabola is expressed as f(x)=ax^2 + bx +c what is the value of c 0

3

3 9/13

8

c = 0

Step-by-step explanation:

A 3-variable linear system of equations is constructed after replacing known values for x and y:

After making algebraic manipulation, the following solution is found:

and and

The value of c is 0.

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb