In ΔIJK, k = 7.7 cm, i = 3.4 cm and ∠J=30°. Find the length of j, to the nearest 10th of a centimeter.

To the nearest tenth = 10.8cm

Step-by-step explanation:

Using the cosine rule

J² = i² + k² + 2ikcosj

J² = 3.4² + 7.7² + 2(3.4)(7.7) cos 30

J² = 11.56 + 59.29 + 52.36cos30

J² = 11.56 + 59.29 + 52.36(0.8660)

J² = 11.56 + 59.29 + 45.35

J² = 116.2

J=√116.2

J= 10.78 cm

To the nearest tenth = 10.8cm

2 x t divided by n

step-by-step explanation:

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )