PLEASE ANSWER PL. TY A standard fair dice is rolled twice.
What is the probability of getting an odd number on the first roll and any factor of 12 on the other?

Step-by-step explanation:

These are independent events, that is the first roll has no impact on the second roll. Because they are independent you can multiply the probabilities of the two events.

Probability of getting a 3 = 1/6. Probability of getting an odd number 1/2 ( 1, 3 or 5 so three good outcomes out of 6 possible outcomes; and 3/6 reduces to 1/2).

Now multiply the two events: 1/6 x 1/2 = 1/12 or approximately 8.3%.

15/36

Step-by-step explanation:

Prob of getting an odd number is 3/6

Prob of getting any factor of 12 is 5/6

The keyword is AND which means time(*)

so the answer would be 3/6*5/6=15/36

this is false ^.^ lol