A show pony weighs at least 900 pounds. After a recent weigh in, the owner of a show pony amended the diet of his pony, increasing the animal's caloric intake, with the hope that the pony would gain weight to be shown in a few months. The data shown in the table and scatter plot below represents the pony's additional daily caloric intake and recorded weight gain (in pounds) of the show pony over the last ten weeks.
Additional Daily Calories ConsumedWeight Gained
(in pounds)
1,5003
1,5757
1,6503
1,7254
1,8008
1,8759
1,95013
2,0257
2,10017
2,17515

Part A: Use the data shown in the table and scatter plot to create an approximate equation for the line of best fit.
Part B: In complete sentences, describe the show pony's weight gain in terms of the units used in the data.
Part C: According to the equation for the best fit line for the data, approximately how much weight would you expect the pony to gain in a week if its additional daily caloric intake for that week is 2,300 calories?

Step-by-step explanation:

Answers:

k = 13The smallest zero or root is x = -10

Work Shown:

note: you can write "x^2" to mean "x squared"

f(x) = x^2+3x-10

f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5

f(x+5) = (x^2+10x+25)+3(x+5)-10

f(x+5) = x^2+10x+25+3x+15-10

f(x+5) = x^2+13x+30

Compare this with x^2+kx+30 and we see that k = 13

Factor and solve the equation below

x^2+13x+30 = 0

(x+10)(x+3) = 0

x+10 = 0 or x+3 = 0

x = -10 or x = -3

The smallest zero is x = -10 as its the left-most value on a number line.

Hope this help :)

A) Best line of fit is last diagram diagonal line. Explanation below.

B) The weight increased by 4 on average with 1 or 2 76 calorie intake increases and then decreased by 6 pounds with every 7 x 75 calorie intakes only to increase by 10 this 6 pound proves a 4 pound overall increase it just proved that calories energy levels created a rapid weight gain and loss sequence when higher calories are consumed in pony's and all active animals.

C) 4 pounds as energy levels are proved.

Equation k= 13 makes sense as √1720.75 = 41  √1867 = 43

where 13 divides x 3-1/2 into the lower group √1650 = √40.6201920232 = 6.4

3-1/2 = 2.5 x 4 = 10

Showing that 3x 4 used = 12 being the higher section numbers 'the last 3 values'

Step-by-step explanation:

Middle value is found when you actually draw it

Alternatively we grid this in order and separate the two data as independents this way we can see the middle values.

x axis = 3  3  4  7  7  8  9  13  15  17

                      < 75                 <75  (<32.5) <75             <75

y axis = 1500 1575  |  1650 1725 | 1800 1875 | 1950 2025| 2100

median = 1800-32.5 midpoint for line of fit is centre origin 0 to coordinate that matches 1867.5 = the median

We see this is somewhere between value 8 and 9 x axis

We check to see the shift of x in the sequence above shown as x axis

And see the numbers median is 10 numbers and 5.5th number is 7.5 is the median so the shift is actually on this number half way to 1867.5

1800- 1575 = 225 + 67.5 = 292.5

We half this value and find 292.5/2 = 146.75

We add this amount to 1574 + 146.75 =  1720.75

1867.5- 146.75 = 1720.75

And use point of origin 0 on the axis grid and consider >1720.75<  to be the exact median and slant the ruler in area of the 1867 and decide on a value being either.

B) The weight increased by 4 on average with 1 or 2 76 calorie intake increases and then decreased by 6 pounds with every 7 x 75 calorie intakes only to increase by 10 this 6 pound proves a 4 pound overall increase it just proved that calories energy levels created a rapid weight gain and loss sequence when higher calories are consumed in pony's and all active animals.

C) 4 pounds as energy levels are proved.

eve and marks ratios are equivalent

step-by-step explanation: