What is the vertex of the quadratic function f(x) = (x-8)(x - 2)?

The vertex is at (5, -9)

Step-by-step explanation:

The vertex is halfway between the zeros

f(x) = (x-8)(x - 2)

0  = (x-8)(x - 2)

x=8 and x=2 are the two zeros

(8+2)/2 = 10/2 = 5

The x coordinate is at 5

The y coordinate is found by substituting the x coordinate into the function

f(5) = (5-8)(5 - 2) = -3 (3) = -9

The vertex is at (5, -9)

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