Pure acid is to be added to a 5% acid solution to obtain 95L of 98% solution. What amounts of each should be used? How many liters of 100% pure acid should be used to make the solution?

Step-by-step explanation:

Equation:

acid + acid = acid

0.05x + 1.0(95-x) = 0.30*95

Multiply thr by 100 to get:

5x + 100*95 - 100x = 30*95

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-95x = -70*95

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x = 70L (amt of 5% solution needed)

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95-x = 25L (amt of 100% solution needed)

How many Liters of 100% acid should be used to obtain the solution?

is should be y = 5x

step-by-step explanation:

correct me if im wrong

what is the rest of the question? ?