Please help! You pick a card at random. Without putting the first card back, you pick a second card at random.

What is the probability of picking a 3 and then picking a 3?

Simplify your answer and write it as a fraction or whole number.

The answer could be 0 or 1 out of 4, because choosing a card at first and not putting it back, then picking a second card at random, it would likely be one in zero attempts to pick 3 again but otherwise that it could be 1 out of 4 because it could be possible picking 3 at the first try.

$30.32

step-by-step explanation:

65.00*.12=2.80

65.00-2.80=57.20

57.20*1.06=60.632

60.632/2=30.316

step-by-step explanation:

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