Find the volume of the pyramid. (AND THE ANSWER IS NOT!!! 160)

V = 80 in^3

Step-by-step explanation:

The volume is

V = 1/3 B h

where B is the area of the base

B = area of the triangle

B = 1/2 (10) * 6

B = 30 in^2

V = 1/3 (30) * 8

V = 1/3 (240)

V = 80 in^3

80 units³

Step-by-step explanation:

The formula for the volume of a triangular pyramid is:

V = (1/3)Bh

where B is the area of the base and h is the height

Now, let's substitute into the formula.

V = (1/3)Bh

V = (1/3)(10)(6)(1/2)h

The base is a triangle, so the area will be: A =  bh/2

The base of the triangle = 10 inches

The height of the triangle = 6 inches

Therefore, the area of the base is (10)(6)(1/2)

V = (1/3)(10)(6)(1/2)h

All we need is the height of the pyramid!

The height is given, 8 inches.

Substitute:

V = (1/3)(10)(6)(1/2)h

V = (1/3)(10)(6)(1/2)(8)

Multiply:

V = (1/3)(10)(6)(1/2)(8)

Because of PEMDAS, you must multiply from left to right.

V = (1/3)(10)(6)(1/2)(8)

V = (3.3)(6)(1/2)(8)

V = (3.3)(6)(1/2)(8)

V = (20)(1/2)(8)

V = (20)(1/2)(8)

V = (10)(8)

V = 80

Therefore, the volume of the triangular pyramid is 80 cubic units.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet