A local company is concerned about the number of days missed by its employees due to ill ness. A Random Sample of 10 employees is selected. The Number of days absent in one year is listed below. An Incentive program is offered in an attempt to decrease the number of days absent. The number of days ansent in one year after the incentive program is listed below. Test the claim that the incentive program cuts down on the number of days missed by employees. Use a=0.05. Assume that the distribution is normally distributied. Employee A B C D E F G H I JDays Absent Before incentive 3 8 7 2 9 4 2 0 7 5Days absent after incentive 1 7 7 0 8 2 0 1 5 5

The incentive program does not cuts down on the number of days missed by employees.

Step-by-step explanation:

The dependent t-test (also known as the paired t-test or paired samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

A paired t-test would be used to determine whether the incentive program cuts down on the number of days missed by employees.

The hypothesis for the test can be defined as follows:

H₀: The incentive program does not cuts down on the number of days missed by employees, i.e. d ≥ 0.

Hₐ: The incentive program cuts down on the number of days missed by employees, i.e. d < 0.

From the information provided the data computed is as follows:

Compute the test statistic value as follows:

The test statistic value is -1.16.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the p-value of the test as follows:

*Use a t-table.

The p-value of the test is 0.1379.

The p-value of the test is very large for all the commonly used significance level. The null hypothesis will not be rejected.

Thus, there is not enough evidence to support the claim.

Conclusion:

The incentive program does not cuts down on the number of days missed by employees

the answer is 510

step-by-step explanation:

15 • 13 = 195

15 • 12 = 180

15 • 5 = 75

12 • 5 = 60

195 + 180 = 375

375 + 75 = 450

450 + 60 = 510