If the expression f^2+g^4-2f+1 is rewritten in the form a^2+(g^2)^2, what must be the value of a?

√(f^2 - 2f + 1) = a

Step-by-step explanation:

We have that:

f^2+g^4-2f+1 =  a^2+(g^2)^2

And we want to find the value of a, so we should isolate it.

f^2 + g^4  - 2f + 1 = a^2 + g^(2*2) = a^2 + g^4

where i used that (x^y)^z = x^(y*z)

We can remove the term g^4 in both sides of the equation and get:

f^2 - 2f + 1 = a^2

now we can apply the square rooth to both sides and get

√(f^2 - 2f + 1) = a

So we just found the value of a.

2. angles qrt and qst both measures 156 degrees.

step-by-step explanation:  

we have been given a diagram of a circle and we are told that measure of arc qvt is 156 degrees.  

we can see from our given diagram that angle qrt and angle qst subtends to arc qvt.

since we know that angles subtended by the same arc at the circumference are always equal.

by angle subtended by same arc theorem, measure of angle qrt and angle qst will be equal to the measure of arc qvt.

therefore, angles qrt and qst both measures 156 degrees and 2nd statement is the correct choice.

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.