Ms. Nina wants to buy candy mix for $1.00 per pound. If she already bought 50 pounds of candy for $1.20 per pound, how many pounds that costs 80 cents per pound must she buy?

She must buy 50 pounds of the other candy in order to have a mix that costs $1 per pound.

Step-by-step explanation:

Her goal is to have a candy mix that has a cost of $ 1.00 per pound, therefore the relation must be equal to 1. She already bought a total of 50 pounds of a $1.2 per pound candy, therefore she spent:

She wants to buy "x" of a 80 cents per pound candy, therefore if we sum it's weigh "x" with 50 pounds, then it must be equal to it's value summed with 60. We have:

She must buy 50 pounds of the other candy in order to have a mix that costs $1 per pound.

50- 250 is correct i did that one too

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)