The sum of the squares of two consecutive positive odd integers is 202. Find the numbers. Please use a let statement and algebraic solution. thanks! :)

9 and 11

Step-by-step explanation:

The sum of the squares of two consecutive positive odd integers is 202.

Let first number be x and other number is (x+2).

According to question,

It is a quadratic equation. The solution of a quadratic equation is given by :

We have, a = 2, b = 4 and c = -198

So,

So, first positive odd integer is 9 and second one is (9+2)=11

answer: 230 miles ( vote ! )

step-by-step explanation:

180.39 minus 17.99 equals 162.4

then divide 162.4 by .80 to get 230