What is the missing constant term in the perfect sqaure that starts with x^2 - 4x

The expression is; x^2 – 4c + 4

Step-by-step explanation:

For the expression to be a perfect square, let us say the constant term should be assigned as ⇒ c;

This creates of following expression;

x^2 - 4x + c

In order to be a perfect square, the discriminant needs to be zero ;

( - 4 )^2 - 4 * ( 1 )c = 0 ,

16 – 4c = 0 ,

4c = 16 ,

c = 4 ,

Solution; The expression is, therefore; x^2 – 4c + 4

answer: answer: d) v= 1/6 bh  

step-by-step explanation:

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