What is the equation for this graph’s lone of best fit.
this is due today pls help

I don't know if your question is multiple choice or not but here's a close estimate to what it should be.

y =  

Step-by-step explanation:

Obviously at a drop of 0 height there would be 0 rebound height so your y-intercept has to be 0.

As for the slope of the line I used the point at 2.5 and 3.

Here are the coordinates (2.5, 1.25) and (3, 1.625)

Find the average rate of change as you see below

1.625 - 1.25 = .375

3 - 2.5 = .5

.375 / .5 = .75 or 3x/4

The points aren't exactly on the line and the graph isn't 100% linear so obviously the equation is not 100% precise. The slope should very close to 0.75 or 3/4.

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

20days louise can read300 pg

step-by-step explanation:

1 day 15 pg 300: 15= 20

x day 300 pg