Hey can anyone pls pls pls help me out in dis math problem rq!!!

my mom deleted my padlet acc

Step-by-step explanation:

Step-by-step explanation:

eq. of line through (-3,-6) and (6,0) is

y+6=(0+6)/(6+3)(x+3)

y+6=6/9(x+3)

y+6=2/3(x+3)

3y+18=2x+6

3y=2x+6-18

3y=2x-12

put x=12,y=4

3×4=2×12-12

12=12

which shows (12,4) lies on above line.

∴inequality may be 3y≤2x-12

put x=0,y=0

0≤-12

which is not true .

Hence (0,0) does not lie in the inequality.

put x=8,y=-2

in the inequality.

3×-2≤2×8-12

-6≤16-12

or-6≤4

which is true.

Hence reqd. inequality is

3y≤2x-12

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

each side has a different length.  

step-by-step explanation: