A stunt man wants to drive a car off a ramp at an angle of 35∘ from the ground. He already has a ramp with an angle of 15∘. He plans to add a second ramp on top to increase the angle to 35∘. What angle measure does the second ramp need to have?

The second ramp needs to have 25°.

Step-by-step explanation:

Required ramp angle for driving the car from the ground = 35°.

First ramp angle = 15°

Therefore, second ramp angle equals required ramp angle minus first ramp angle, which is = 35° - 15° = 20°

The 20° ramp angle will make the total ramp angle to be equal to 35°.

That is 15° + 20° = 35°

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

on plase n