The diagram below models the layout at a carnival where G, R, P, C, B, and E are various locations on the grounds. GRPC is a parallelogram.

Parallelogram GRPC with point B between C and P forming triangle GCB where GC equals 375 ft, CB equals 325 ft, and GB equals 425 ft, point E is outside parallelogram and segments BE and PE form triangle BPE where BP equals 225 ft.

Part A: Identify a pair of similar triangles.

Part B: Explain how you know the triangles from Part A are similar.

Part C: Find the distance from B to E and from P to E. Show your work.

Down below

Sorry if it's wrong...

Step-by-step explanation:

A and B. The similar triangles must be GBC and BPE because they are the only two.

You can tell that GBC = PBE because of vertical angles.

Then, you can see that GCP is an angle on the parallelogram.

GCP is also an angle in GBC

GCP + RPC = 180

RPC + BPE also = 180

GCP = BPE

GBC ≈ BPE by AA similarity.

C. So since those two triangles are congruent, you can find which sides are similar. 225 : 325 is the ratio.

Simplify: 9 : 13

Apply to the rest:

9 : 13 = x : 425

9 : 13 = x : 375

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

the answer will be b x² +x-1

step-by-step explanation: