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The height of an object launched upward from ground level is given by the function s(t) = -4.9t2 + 78.4t, where s(t) is the height in meters and t is the time in seconds. Arrange the time intervals in ascending order of the object's magnitude of average velocity over the interval.

the distance of  the object before it  hits the ground after launch is t = 1.592 seconds

Step-by-step explanation:

The height of an object launched upward from ground level is given by the function s(t) = -4.9t² +7.8t

when the object reach the ground then s(t) = 0

So;  -4.9t² +7.8t = 0

-4.9t² +7.8t + 0 = 0

By using the quadratic equation

where; a = -4.9 ; b = 7.8 and c = 0

Hence;  the distance of  the object before it  hits the ground after launch is t = 1.592 seconds

-2/

answer: x=3 and y=4

step-by-step explanation: