Pedro has determined that the probability his shot will score in a lacrosse game is 0.30. What is the probability that he will score on two consecutive shots? 0.09 0.15 0.30 0.60 Jillian has three different bracelets (X, Y, and Z) to give to her friends as gifts in any order she prefers. If bracelet Y is chosen first, in how many ways can Jillian give out the bracelets? 1 2 3 4

a) 0.09

b) 2 ways

Step-by-step explanation:

a) Probability Pedro's shot will score will be given as) :

P(score) = 0.30

The probability he will score in 2 consecutive shots will be calculated as:

P(score) * P(score)

= 0.30 * 0.30

= 0.09

Therefore, probability he will score in 2 consecutive shots is 0.09

b) Jillian has 3 bracelets: X, Y, & Z as a gift. If bracelet Y is chosen first, the number of ways Jillian can give out the bracelets since bracelet Y is chosen first, she will have 2 bracelets remaining. So, number of ways to distribute these 2 bracelets are :

= 2!

= 2 * 1

= 2

Which could be in this order:

YXZ or YZX

Therefore, the number of ways if Y is chosen first is = 2 ways

last one.

step-by-step explanation:

last one.

generally speaking, the others follow some sort of pattern that correlates to either linear (looks like a straight line) or sinusoidal (looks like an s).

the last one is just a random cloud of points that doesn't correlate to any particular known order.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}