Problema: Se guarda una moneda antigua en una caja cubica de tal forma que el contorno de la moneda toca las 4 paredes de la caja, si la base de la caja tiene un perímetro de 24 cm ¿Cual es el área de la moneda?

50.24 cm^2

Step-by-step explanation:

This can be translated to:

An old coin is kept in a cubic box in such a way that the outline of the coin touches the 4 walls of the box, if the base of the box has a perimeter of 24 cm. What is the area of the coin?

The fact that the coin touches the interior of the box means that the diameter of the coin is equal to the side lenght of the box.

The perimeter of the box is 24 cm, and the perimeter of a square is equal to:

P = 4*L

where L is the side lenght of the square.

24 cm = 4*L

L = 24cm/4 = 8cm

Now we know that the diameter of the coin is 8cm

Now, the area of a circle (the coin) is equal to:

A = 3.14*(d/2)^2

where d is the diameter, so we have:

A = 3.14*(4cm)^2 = 50.24 cm^2

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