Graph the linear function.
f(x)=x+2
HELP PLEASE

Hey there!

Graphing this will be similar to graphing slope intercept equations (y=mx+b).

As you can see, we have a slope of 1 and a y-intercept of two when you look at the equation and match it up with the slope intercept form Let's look at each answer option and see which one fits.

GRAPH A

Graph A does have a y-intercept of two. This means that the line crosses the y-axis at two units up from the origin. However, it has a negative slope because it is going downwards rather than upwards. The slope of our function is positive, so Graph A does not match.

GRAPH B

Graph B does have a positive slope of one (a slope of one means that it goes diagonally across every small square on the grid), but it's y-intercept is -2 because it hits the y-axis at 2 down from the origin. Therefore, Graph B does not match this function.

GRAPH C

Graph C both goes downward (negative slope) and it hits the y-axis at -2 instead of 2 (wrong y-intercept). Therefore, Graph C does not match the function.

GRAPH D

Graph D has a y-intercept of 2 and it has a positive slope of one! Therefore, Graph D does match this function.

The correct answer is Graph D.

I hope that this helps! Have a wonderful day!

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents

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step-by-step explanation: