What is the coordinate for the image of point H(2, –6) under a 90° clockwise rotation about the origin? H’(–6, –2) H’(6, –2) H’(–6, 2) H’(6, 2)

explanation:

step-by-step explanation:

can i see a photo of the question so i can you?

hello there!

i believe the answer is

(cot2+1)/sec2=cot2

    csc2/sec2=cot2

  (1/sin2)/(1/cos2)=cot2

  (1/sin2)(cos2/1)=cot2

  cos2/sin2=cot2

  (1/tan2)=cot2

  (cot2)=(cot2)

hope this !

hyperz ^_^

first the equation needs to be simplified. so the equation would now look like:   52-24+11

then you multiply.

and when you multiply, you will get the answer of 39.