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Mathematics, 30.05.2020 11:58 Bombin1118

Rewrite the equation by completing the square. X2βˆ’2x+1=0x^{2}-2x+1 = 0x2βˆ’2x+1=0x, squared, minus, 2, x, plus, 1, equals, 0 (x+(x + {}(x+left parenthesis, x, plus )2=)^2 = {})2=right parenthesis, squared, equals

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Rewrite the equation by completing the square. X2βˆ’2x+1=0x^{2}-2x+1 = 0x2βˆ’2x+1=0x, squared, minus, 2,...
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