A used car dealer sells SUVs and cars. Of all the vehicles, 70% are cars. Of all the vehicles, 10% are black SUVs. What is the probability that an SUV chosen at random is black? Round your answer to the nearest tenth of a percent.

0.3

Step-by-step explanation:

From the question,

A used car dealer sells SUVs and cars. Of all the vehicles, 70% are cars. Since 70% are cars, SUV will be (100% - 70%) = 30%. Of all the vehicles, 10% are black SUVs. To calculate the probability than an SUV chosen is black goes thus:

P(A|B) = P(A and B) / P(B)

P(SUV | black) = P(SUV and black) / P(suv)

P(suv | black) = 10%/ 30%

P(suv | black) = 0.1/0.3

P(suv | black) = 0.3

113.1

step-by-step explanation:

v=4

3πr3=4

3·π·33≈113.09734