A bag contains 3 red balls and two blue balls. A ball is taken out random from the bag and then put back. A second ball has been taken out of the bag. What is the probability that: (a) both balls are red, (c)b both balls are the same color, (c) at least one of the balls is red. Answer

a . 9/25

b. 13/25

c. 3/5

Step-by-step explanation:

Firstly, we add the number of balls to get the total number of balls = 3 + 2 = 5 balls

P(R) = number of red/total number of balls = 3/5

P(B) = number of blue/total number of balls = 2/5

Since the experiment is with replacement, whatever ball picked would be returned

a. Probability of both balls being red = P(R) * P(R) = 3/5 * 3/5 = 9/25

b. Probability of both balls being same color;

That is : probability of both balls being red or both being blue

Mathematically that would be;

P(R) * P(R) or P(B) * P(B)

whenever we have or in probability, what we do is to add ;

= (3/5 * 3/5) + (2/5 * 2/5) = 9/25 + 4/25 = 13/25

C. at least one of the balls is red

what this means is that both are red or one of the two is red.

Mathematically;

P(R) * P(R) or P(B) * P(R)

= (3/5 * 3/5) + (3/5 * 2/5)

= 9/25 + 6/25 = 15/25 = 3/5

10 * 563.67 = 5636.7

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.