The speeds in miles per hour of seven randomly selected qualifiers for the Indianapolis 500 (in 2012) are listed below. Estimate the mean qualifying speed with 95confidence. Round your answers to four decimal places.

223.684 222.929 226.240 224.037 226.484 225.172 223.422

Mean qualifying speed

= 224.5669mi/hr

Speed that passed the average/mean

= 226.240mi/hr ,224.037mi/hr 226.484mi/hr, 225.172 mi/hr

Step-by-step explanation:

Let's understand what mean is then understand what mean qualifying speed is.

First mean is like the average of the seven speed listed below.

So let's find the mean.

Mean = (223.684+ 222.929+ 226.240

+224.037 +226.484+ 225.172

+223.422)/7

Mean = 1571.968/7

Mean = 224.5669

So the mean qualifying speed is those speed that qualifies when the mean is taken, i.e the speed that crossed the average.

Mean qualifying speed are

=226.240 ,224.037,226.484

, 225.172

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)