A box of chocolates contains five milk chocolates and six dark chocolates. Mike randomly picks a chocolate and eat it. Then Mike randomly picks another chocolate and eats it. Determine the probability Mike eats two milk chocolates. Round to the hundredths place.

0.182

Step-by-step explanation:

For the first selection, the probability of picking a milk chocolate bar is equal to the number of milk chocolate bars divided the total number of bars, this is:

p1 = 5/(6 + 5) = 5/11

In the second selection we have the same equation, but now we have  4 milk chocolate bars (because one is alredy taken)

p2 = 4/(4 + 6) = 4/10

the joint probability is:

P = p1*p2 = (5/11)*(4/10) = 0.182

answer:

your answer is: c. 196 7/8 in^3.