Given that the commuter used public transportation, find the probability that the commuter had a commute of 60 6060 or more minutes. P ( 60 + minutes ∣ public transportation ) = P(60+ minutes ∣ public transportation)=P, left parenthesis, 60, plus, start text, space, m, i, n, u, t, e, s, space, end text, vertical bar, start text, space, p, u, b, l, i, c, space, t, r, a, n, s, p, o, r, t, a, t, i, o, n, end text, right parenthesis, equals

Complete Question

The two-way table below gives the thousands of commuters in Massachusetts in 2015 by transportation method and one-way length of commute.  

Step-by-step explanation:

From the table above

Total Number of commuters who used public transportation=329

Number of commuters who spent 60 or more minutes on public transportation=108

Therefore:

Given that a commuter used public transportation,  the probability that the commuter had a commute of 60 or more minutes:

P ( 60 + minutes ∣ public transportation ) =

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it