What are the coordinates of the vertex of a parabola whose equation is y+4=2(x−7)^2?

To find the vertex, the easiest way is to use vertex form; y= a(x - h)^2 + k where (h, k) is the vertex.

These are the steps to convert your equation to vertex form;

START: y+4 = 2(x - 7)^2
Subtract 4 from both sides: y = 2(x - 7)^2 - 4

The “h” and “k” are 7 and -4, respectively.

So... the vertex is (7, -4)

And there you have it! Your final answer is (7, -4)!

I recommend that you learn how to identify the different forms of equations!

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